The category that is chosen for today is Mirror quiz. Let us help you with solving the crossword clue "A P E —, England Test cricketer who hit 101 against New Zealand in Auckland in 1971" quick!
Check out the BEST answer below:
Understanding Today's Crossword Puzzle
The clue for today's crossword puzzle is "A P E, England Test cricketer who hit 101 against New Zealand in Auckland in 1971" and the answer for this clue today is "KNOTT". Let's explore why this clue has this answer:
1. The clue starts with "A P E". This indicates that we are looking for a three-letter word that starts with the letters A, P, and E.
2. The clue then provides additional information about the person we are looking for – an England Test cricketer who hit 101 against New Zealand in Auckland in 1971.
3. The answer to this clue is "KNOTT".
So, how does "KNOTT" match the given clue?
1. "KNOTT" is a three-letter word that starts with the letters A, P, and E, as indicated by the clue.
2. Alan Knott is the England Test cricketer who matches the description mentioned in the clue. He scored 101 runs against New Zealand in Auckland in 1971.
In conclusion, the answer "KNOTT" accurately corresponds to the given clue. It meets the criteria provided in the clue, which includes a three-letter word starting with A, P, and E, as well as identifying the England Test cricketer who scored 101 runs against New Zealand in Auckland in 1971.
The Crossword clue "A P E —, England Test cricketer who hit 101 against New Zealand in Auckland in 1971" published 5 time/s & has 1 answer/s.
Crossword | Date | Answer |
Mirror quiz | 24 October 2020 | KNOTT |